197.Rising Temperature

197.Rising Temperature

难度:Easy

给定一个 Weather 表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id。

``` +---------+------------------+------------------+ | Id(INT) | RecordDate(DATE) | Temperature(INT) | +---------+------------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------------+------------------+ 例如,根据上述给定的 Weather 表格,返回如下 Id:

+----+ | Id | +----+ | 2 | | 4 | +----+

需要認識`DATEDIFF`函數,主要是比較日期的,前者大返回1,後者大返回-1;

Write your MySQL query statement below

SELECT weather.id AS 'Id' FROM weather JOIN weather w ON DATEDIFF(weather.RecordDate, w.RecordDate) = 1 AND weather.Temperature > w.Temperature ;

```

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