示例 1:
​
输入: [[1, 5, [2, 3]], [2, 3, []], [3, 3, []]], 1
输出: 11
解释:
员工1自身的重要度是5，他有两个直系下属2和3，而且2和3的重要度均为3。因此员工1的总重要度是 5 + 3 + 3 = 11。

/*
// Employee info
class Employee {
public:
    // It's the unique ID of each node.
    // unique id of this employee
    int id;
    // the importance value of this employee
    int importance;
    // the id of direct subordinates
    vector<int> subordinates;
};
*/
class Solution {
private:
    int getIndex(vector<Employee*> employees, int id)
    {
        for(int i=0;i<employees.size();i++)
            if(employees[i]->id ==id)
                return i;
        return -1;
    }
public:
    int getImportance(vector<Employee*> employees, int id) {
        int ind=getIndex(employees,id);
        int res=employees[ind]->importance;
        for(auto i: employees[ind]->subordinates)
        {
            int n=getIndex(employees,i);
            if(employees[n]->subordinates.empty())
            res+= employees[n]->importance;
            else
                res+=getImportance(employees,employees[n]->id);
​
        }
​
        return res;
​
    }
};