难度:Easy
写一个程序,输出从 1 到 n 数字的字符串表示。
如果 n 是3的倍数,输出“Fizz”;
如果 n 是5的倍数,输出“Buzz”;
3.如果 n 同时是3和5的倍数,输出 “FizzBuzz”。
示例:n = 15,返回:["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
简单题,
class Solution {public:vector<string> fizzBuzz(int n) {int s=res.size();if(s>=n)return vector<string>(res.begin(),res.begin()+n);for(int i=s+1;i<=n;i++)if(i%15==0) res.push_back("FizzBuzz");else if(i%5 ==0) res.push_back("Buzz");else if(i%3 ==0) res.push_back("Fizz");else res.push_back(to_string(i));return res;}private:vector<string> res={"1","2","Fizz","4","Buzz"};};